Question

How do I solve 75y^3+100y^2-3y-4=0

Answer 1

\[75y^{3}+100y^{2}-3y-4=0\]

Answer 2

One way is to factor the left hand side

Answer 3

we can factor by grouping to get


75y^3+100y^2-3y-4

(75y^3+100y^2)+(-3y-4)

25y^2(3y + 4) - 1(3y + 4)

(25y^2 - 1)(3y + 4)

(5y - 1)(5y + 1)(3y + 4)

-------------------------------------------------------

So that means

75y^3+100y^2-3y-4 = 0

is the same as

(5y - 1)(5y + 1)(3y + 4) = 0

Answer 4

once you get to (5y - 1)(5y + 1)(3y + 4) = 0, you would use the zero product property

Answer 5

Awesome. Thanks.

Answer 6

sure thing