Brain is trying to pull Julie on a sled across a flat snowy field. Brain pulls on a rope attached to the sled. Brian's pulling force is directed forward and upward at an angle of 30 degrees above horizontal. Julie's mass is 50 kg, and the sled's mass is 8 kg. If the coefficient of static friction between the sled runners and the snow is 0.10, how much force must Brain exert on the rope to start moving the sled?
W = mg W= (58) (9.81) W= 569 N \[F= \mu _{s} R\] \[\mu _{s} = .1 \] R = 58? or 569 N ?
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the answer should be 62 N
you started out correctly the friction on the runners will be 0.1x569 =56.9Newtons
so now the horizontal component of the pulling force has to be at least 56.9N
@ProfBrainstorm how do i find the answer though? it is suppose to be 62
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okay, so if we call the pulling force along the direction of the rope F, what will it's component in the horizontal direction be, in terms of F and the 30 degree angle ?
@ProfBrainstorm tht would mean F= CAH --> F= 56.9/ cos(30), but that doesnt give me 62
I get an answer of 65.7 N who says it should be 62 ?
the book
well based on the numbers given here I'm fairly sure the answer is 65.7 did you put the correct numbers in the question ? It could be a typo error in the book, it happens.
Yeah I am sure, this is the problem I see in my book, and the answer is 62 N in the back of the book
The answer in the book is wrong
@ProfBrainstorm haha, okay, thanks for all your help!
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