Ask your own question, for FREE!
Physics 20 Online
OpenStudy (anonymous):

Two vectors are defined as follows: A⃗ =(−2.2m)x^ and B⃗ =(1.4m)y^ Is the magnitude of 1.4 A⃗ greater than, less than, or equal to the magnitude of 2.2 B⃗ ? 1) |1.4A⃗ | is greater than |2.2B⃗ | 2) |1.4A⃗ | is less than |2.2B⃗ | 3) |1.4A⃗ | is equal to |2.2B⃗ | Explain Please!!

OpenStudy (anonymous):

@ProfBrainstorm

OpenStudy (anonymous):

the magnitude of any non zero vector is positive - that should help

OpenStudy (anonymous):

sorry haha this is my first physics class ever haha

OpenStudy (anonymous):

from the information given, what is the magnitude of A ?

OpenStudy (anonymous):

-2.2

OpenStudy (anonymous):

right

OpenStudy (anonymous):

that is the x component, which happens to be the only component of this vector but the magnitude is always positive, like i said above

OpenStudy (anonymous):

imagine drawing that vector x, and ask yourself, how long is it - that is the magnitude

OpenStudy (anonymous):

sorry, A, not x

OpenStudy (anonymous):

im confused haha i thought -2.2 was the magnitude.. so i should just draw the 1.4 for A?

OpenStudy (anonymous):

look again at what A is, in the question

OpenStudy (anonymous):

-2.2 lol

OpenStudy (anonymous):

that's the x component, but what is the length of that line if you just draw it ?

OpenStudy (anonymous):

i have no clue

OpenStudy (anonymous):

1.4?

OpenStudy (anonymous):

NO : (

OpenStudy (anonymous):

ok, if i draw a line, starting out at the origin and ending at the point (-2.2, 0), how far has my pencil moved ?

OpenStudy (anonymous):

Can you draw a sketch of the vector A ?

OpenStudy (anonymous):

|dw:1410635574232:dw| you can add it to this set of axes starting at the origin

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!