Question

integral [0,pi] of (d(theta))/(A-Bcos(theta))

Answer 1

\[\int\limits_{0}^{\pi} \frac{ 1 }{ A-Bcos(\theta) }\]

Answer 2

try
\(\theta = \tan (x/2)\)

Answer 3

***

\(x = \tan (\theta/2)\)

Answer 4

get cos theta in the form of tan theta/2

find dtheta also

Answer 5

its not going to be easy later too, but its a good start

Answer 6

hartnn's right.

Answer 7

\[\cos 2x=\frac{ 1-\tan ^2x }{ 1+\tan ^2x }\]

Answer 8

Can you guy's simplify it more?

Answer 9

t = tan theta/2

dt = 2t/(1+t^2)

cos theta = (1-t^2)/(1+t^2)

plug all these in the integral

few algebraic steps, cancel out 1+t^2

then tell us what you get your new integral in only 't'