if log (x+y)/7=1/2(logx+logy) prove that x/y+y/x=47
2 log [(x+y)/7] = log x + log y you know logarithm properties ?
how will you simplify log x + log y ?
no? / yes? / just give me answer?
hi are you speaking to me?
hey dane, yes :) since you asked that question, i wanted to know whether you know some logarithm properties which will help us solve this problem :)
cool !!!:) yes i know the logarithm properties
nice , how will you simplify log x + log y ?
log xy?
correct! now \(\log a^b = b \log a\) so if i had [b log a], i could write it as \(\log a^b\) right ? similarly how will i write 2 log [(x+y)/7] as ?
log(x+y/7)^2
oh wow, you're good at logarithms :) \(\log [(x+y)/7]^2 = \log xy\) so we can simply write \( [(x+y)/7]^2 = xy\) isn't it ? can you simplify that further ?
expand the left side
everything after this is purely algebraic :)
can you help me with the key to type square on the keyboard instead of typing ^
thanks a million god bless you
you gone?
just went to help other users too :) and you're most welcome ^_^ type \(x^2 \) as `\(x^2 \)`
so kind of you !! can i ask another?
sure :) ask as many as you want :)
since you're new here, \(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)
@hartnn !!! yay
thanks
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