Evaluate the limit. limx→0{(3.5+4.5x)^3−42.875}/x=
just plug in x=0
I tried, doesn't it just equal 0/0?
@hartnn
-42.875/0 which is \(-\infty \)
oops sorry, i misread the question
ok, so 3.5^3 = 42.875
we have the form of \(a^3-b^3\) here right ?
@hartnn I tried all these already and nothing seems to be working. I've working on this problem for half an hour now, thats why I'm asking on here finally
use the formula \((a-b)(a^2+ab+b^2)\) a= 3.5 +4.5 x b= 3.5
@hartnn so after plugging in the values for a &b I should have the answer?
did you try plugging in? after that there will be 'x' in the numerator which will get cancelled with the 'x' in the denominator and then you can directly plug in x=0
so I got : (3.5 - 4.5x)(3.5^2+15.75x+3.5^2)
@hartnn
is that the correct equation?
a-b is just 4.5 x isn't it ?
you took a = 3.5, b= 4.5x thats not correct
a= 3.5 +4.5x b=3.5
ok so then the correct equation is: (4.5x)(3.5^2+15.75x+3.5^2) ?
or (4.5x)(7^2+15.75x)? @hartnn
no...a= 3.5 +4.5x so a^2 =(3.5 +4.5x)^2
I'm kind of confused now. so if I calculated your equation the answer would be = 23.75? @hartnn
@hartnn nevermind that answer didn't work either
show each of your steps, i'll help u spot the error
okay hold on let me type it out
Formula: (a−b)(a2+ab+b2) a= 3.5 +4.5 x b= 3.5 3.5+4.5x - 3.5 = 4.5x (4.5x)({[3.5+4.5x]*2}+{[3.5+4.5x]*3.5}+[3.5*2])
@hartnn that's the equation I got
ok, thats correct now cancel out x and plug in x=0 in the remaining part
the last part is 3.5^2 not 3.5*2
\((4.5x)({[3.5+4.5x]^2}+{[3.5+4.5x]*3.5}+[3.5^2])\)
\((4.5)({[3.5+4.5(0)]^2}+{[3.5+4.5(0)]*3.5}+[3.5^2])\)
@hartnn I might be wrong but so is 70.875 the answer?
using calculator, its 165.375
4.5*3*3.5^2
Yeah that was the correct answer, but how did you get the 4.5*3*3.5^2? I thought the first two parts of the equation equaled 0? so it would be 4.5*3.5+3.5^2
\((4.5)({[3.5+4.5(0)]^2}+{[3.5+4.5(0)]*3.5}+[3.5^2])\) \((4.5)({[3.5]^2}+{[3.5]*3.5}+[3.5^2]) \\ 4.5 ([3.5^2]+[3.5^2]+[3.5^2])\)
a+a+a=3a
@hartnn oh okay, I see now!
@hartnn thank you so much
welcome ^_^
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