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Mathematics 15 Online
OpenStudy (anonymous):

help http://gyazo.com/64ea82c2e84534ca2383c347ba811210

OpenStudy (anonymous):

You'd multiply 6 and 2 because there's 6 numbers on the die and you'd roll it twice. Then you'd square that answer, which would give you the number of combinations you can get. That would only give you the denominator. The numerator would be 2.

OpenStudy (anonymous):

Then simplify the fraction.

OpenStudy (anonymous):

wait so 12^2=144

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

So you'd have \[\frac{ 2 }{ 144 }\] but you need to simplify it.

OpenStudy (anonymous):

1/72

OpenStudy (anonymous):

Yes, good job!

OpenStudy (kropot72):

The probability of getting a 6 on the first roll is 1/6. The probability of getting a 1 on the second roll is also 1/6. The two events are independent, therefore the required probability is given by: \[\large P(4\ then\ 1)=\frac{1}{6}\times\frac{1}{6}=you\ can\ calculate\]

OpenStudy (anonymous):

1/36 thanks

OpenStudy (kropot72):

You're welcome :)

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