Question

(2x)^-1++1/2x^-1-1

Answer 1

Your problem has two "+'s" is there supposed to be a number between them?

Answer 2

\[(2x)^{-1} + \frac{ 1 }{ 2x^{-1}} -1 = \frac{ 1 }{ 2x } + 2x - 1\]....now can you do it?

Answer 3

\[\frac{ 1 + 4x^2 + 2x }{ 2x } => (2x +1 )(2x +1)/2x\]

Answer 4

thanks guys

Answer 5

\[\left( 2x \right)^{-1}+\frac{ 1 }{ 2 ~x ^{-1} }-1=\frac{ 1 }{ 2 x }+\frac{ x }{ 2 }-1=\frac{ 1+x^2-2x }{ 2x }\]\[=\frac{ \left( x-1 \right)^2 }{ 2 x }\]