Question

PLEASE HELPPP (:

In triangle ABC, a = 12, B = 25°, and C = 45°. Find b.

5.4

6.6

7.2

22

Answer 1

find angle A first
A+B+C =180

then you can use sine law

Answer 2

\(\large \dfrac{a}{\sin A} = \dfrac{b}{\sin B}\)

Answer 3

then would it be A= sin^-1(12) B= sin^-1(25) ??

Answer 4

??

first find A!
A+B+C =180
B =25
C=45

Answer 5

A+B+C = 180 because A,B,C are angles of a triangle.

Answer 6

looks like you're going in the right direction

Answer 7

@hartnn ohhhh!! then A= would be 110! my bad (:

Answer 8

yess

now apply sine law

Answer 9

12/ sin 110 = b/ sin 25

find b

Answer 10

sin25*12/sin110=b ?? @hartnn

Answer 11

im confused now

Answer 12

yes, calculate that

Answer 13

where r u confused jazi ?

Answer 14

@hartnn umm i got this?? 5.396891

Answer 15

thats correct :)

Answer 16

\(5.396 \approx 5.4\)

Answer 17

okay, I see now..confused myself guys

Answer 18

okay i got it till there! so now how would i find the total answer??

Answer 19

just look at the options :P

Answer 20

b=5.4!

Answer 21

@hartnn hahahah sorry! theres only two more questions that im confused with! could you maybe check them out??

θ is in standard position, and the terminal side passes through the point (3, -5).

Find sinθ.



-5sqrt31/31

-5sqrt34/34

-3/5

-4/5

Answer 22

find sintheta!

Answer 23

point = (r cos theta , r sin theta)

so to get sin theta,
do -5/r
know how to find 'r' ?

Answer 24

sin^-1(-5)??

Answer 25

\(r = \sqrt {3^2 +(-5)^2}\)

Answer 26

i think i got the answer!!
-5sqrt34/34

Answer 27

and thats correct :)