Question

For the reaction
?ZnO+?HCl →?ZnCl2+?H2O,
what is the maximum amount of ZnCl2 which could be formed from 12.04 g of ZnO and 1.71 mol of HCl?
Answer in units of g

Answer 1

I'm actually not sure. I am trying to help, but this has some parts that are beyond me. I apologize.

Answer 2

First step would be to balance the equation.

ZnO + 2HCL --> ZnCl2 + H2O

Now the maximum amount of Zinc Chloride formed depends on the LIMITING reagent. Find the number of moles of ZnO..

12.04/65+16 which gives us 0.153 moles.

You have 1.71 moles of HCl, when you have 0.153 moles of ZnO. According to the equation, you need 0.306 moles of HCl to fully react. Hence, ZnO is the LIMITING reagent. Once ZnO is finished, you wont have any more reaction, despite the left over amount of HCl.

The mol ratio of ZnO and ZnCl2 is from our equation, 1 : 1

Now chuck the # of moles in, 0.153 * molar mass of ZnCl2

0.153 * ZnCl2 molar mass gives you your answee.