Question

Prove that the general equation y'=p(x) +q(x)y+r(x)y^2 has a general solution y(x)=Yp+z(x), where z(x) is a solution of z'-(q+2rYp)z=rz^2.

Answer 1

It likes you just have to plug in and verify

Answer 2

well into the first equation for sure
but I wonder if we also need to find z too to help verify

Answer 3

what is Y ?

Answer 4

Yp is the particular solution