Question

write each expression as the product of two bionomials 2x(y+4)+3(y+4) i don't understand how to figure this out

Answer 1

2x(y+4)+3(y+4)
2x(y+4) has the factor (y+4) and 3(y+4) also has the factor (y+4).
Pull out the common factor:
2x(y+4)+3(y+4) = (y + 4)(2x + 3)

Answer 2

so what is the common factor?

Answer 3

(y + 4) is the common factor.

Answer 4

okay thanks i think i understand now

Answer 5

You are welcome.

Answer 6

What we did was we noticed that in 2x(y+4)+3(y+4)
the (y+4) multiplies 2x and then multiplies 3 and adds them.
So we can factor out (y+4) and write it as (y+4)(2x + 3).

Answer 7

The answer is a product of two binomials. Binomial means TWO terms.
y + 4 has two terms and so it is a binomial.
2x + 3 also has two terms and so it is also a binomial

Answer 8

so you wouldn't use FOIL?

Answer 9

i actually have another question if you aren't busy

Answer 10

You wouldn't use FOIL here because they are not asking you to expand and then simplify. Here they want you to factor 2x(y+4)+3(y+4). But instead of using the word "factor" they are just saying it in a roundabout way as: write it as a product of two binomials.

Go ahead and post your other question.

Answer 11

okay i get that one now... the other question is x^2-x-6 the same directions apply

Answer 12

x^2 - x - 6 = (x + ?) * (x + ?)
We need to come up with numbers where the question marks are.
The two numbers should be such that they add to the coefficient of the middle term (-1) and they should multiply to the constant term (-6). Can you come up with two such numbers?
Take the constant term and write all possible pairs of factors for it.
Can you list all factors of -6?

Answer 13

okay so 1,6
2,3
-1,-6
and -2,-3

Answer 14

Slight modification:
Factors of -6:
1 and -6
-1 and 6
2 and -3
-2 and 3

All of these pairs multiply to -6.
But which pair adds to -1?

Answer 15

2 and -3 correct?

Answer 16

Correct.
x^2 - x - 6 = (x + 2) * (x - 3)

That is it.

Answer 17

thank you...are you a math teacher?

Answer 18

You are welcome.
Not a teacher. Just volunteering here to help out with math.

Answer 19

do you know a lot of algebra 2/ trig because thats what I'm studying and im frankly not very good at math

Answer 20

There are many, many people here who are good at those. Just post the questions one at a time and when it is answered satisfactorily you can close that question and post a new one. Also, if a number of people post replies and you like one of the replies the best you can click on the "Best Response" button next to their reply.

Answer 21

well i guess it's pretty clear that this is my first time on the website