Question

How many grams of vanadium, V, would contain the same number of atoms as 32.066 g of sulfur, S?

Answer 1

First let's calculate the number of atoms in 32,066 g of S

being a little technic
moles= mass/molar mass=32,066g/32,064g= 1 mol .

Each mole has 6.02xE23 atoms
then we have that..... 32.066g(S) has 6.02E23 atoms

Then we can get to the conclusion, that 1 mol of V has the same number of atoms because it has 6.02E23.

Now the only thing to do is find out the mass in that quantity of V.

Answer 2

the mass of V is 50.942 so what do i do next though?

Answer 3

Mol= mass/molar mass

then... Mass= mol x molar mass.

Answer 4

I did what you said and it give me the same grams in the problem... theres 32.066 gram of V as well?

Answer 5

Nope.

Mass= 1 mol (V)x 50,94g/mol= 50,94 g

if you are aware of the sig figs this is not the correct result.

Answer 6

50,94g is not the mass, that is the molar mass.

There is a BIG difference.

Answer 7

the moles i get is
0.62946 x 50.942 (molar mass) = 32.066 sig fig rounded so isn't the same though??

Answer 8

where did you get that 0.62....?

Answer 9

mole = mass/molar mass
and i get 0.62
then i plugged the moles into the other part u gave an got the answer i got

Answer 10

Did you read what i wrote?

that equation is to demonstrate where i got the second one.