Question

Evaluate. (IMAGE IN DESCRIPTION)
a. 1/8
b. -1/32
c. 1/32
d. -13/63
e. none of the above

Answer 1

i'm getting A?

Answer 2

\(\large a(a^2-a^2b)\)
\(\large -\frac{1}{2}((-\frac{1}{2}^2)-((-\frac{1}{2}^2)\frac{3}{4}))\)

what is -1/2 squared?

Answer 3

1/4?

Answer 4

that's a start. let's simplify
\(\large -\frac{1}{2}(\frac{1}{4}-(\frac{1}{4}*\frac{3}{4}))\)

Answer 5

the little asterisk signifies multiplication
\(\large -\frac{1}{2}(\frac{1}{4}-(\frac{1}{4}*\frac{3}{4}))\)
\(\large -\frac{1}{2}(\frac{1}{4}-\frac{3}{16})\)

Answer 6

i redid it and got -9/16

Answer 7

i see what i missed.

Answer 8

is that the answer i should be getting?

Answer 9

let's see
\(\large -\frac{1}{2}(\frac{1}{4}-\frac{3}{16})\)
\(\large -\frac{1}{2}(\frac{4}{16}-\frac{3}{16})\)
\(\large -\frac{1}{2}(\frac{1}{16})\)
\(\large -\frac{1}{2}*(\frac{1}{16})\)
\(\large -\frac{1}{32}\)

Answer 10

where did i get my 9 from? i see what you did there. i'm looking over mine and i don't see how i got a -9 numerator. that explains alot

Answer 11

lol I'd suggest you post a pic of your work as I can't see where you got it from either.

Answer 12

i did everything the exact same way as you did until the -1/2(1/16) and from there i got the -9/16 somehow?

Answer 13

I don't see how D:
you just multiply the 2 terms together
hmm

Answer 14

i know. i think i got my math work mixed together. time to start a new piece of scratch paper. lol

Answer 15

that's great to hear. the best way to learn math is through examples and doing work

Answer 16

yeah, i have 50 practice problems for an upcoming exam so the ones i don't understand i'm posting to get help with. you're helping me understand so much. i appreciate it. i really need to pass this class.

Answer 17

I'm also cheaper than a tutor which is pretty awesome

Answer 18

lol yes, which is something i can't afford right now, which is why i turn to open study :p so you're literally the best.

Answer 19

*curtsies* thank you