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OpenStudy (anonymous):
Simplify (IMAGE IN DESCRIPTION)
a. c^5 y^3/a b^3 x^6
b. a^-6 c^6 y^3/a^-4 b^3 x^-9
c. a^3 c^5 y^3/ b^3 x^6
d. a^3 c^5 y^3/b^3
e. none of the above
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OpenStudy (anonymous):
OpenStudy (anonymous):
@bibby
OpenStudy (bibby):
ew. let's start with the concepts.
\(\large x^{-m}=\frac{1}{x^m}\)
\(\large \frac{a^m}{a^n}=a^{m-n}\)
OpenStudy (bibby):
does that say b^0 on the denominator?
OpenStudy (anonymous):
yes. sorry the pic didn't come out clear.
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OpenStudy (bibby):
another concept then. \(a^0=1 : x \ne 0\)
anything to the 0 is 1 (except 0)
OpenStudy (anonymous):
okay so now we have a^-2/b^1
OpenStudy (bibby):
not exactly. following our rules, we have this: \(\huge \frac{a^{-2}}{b^0}=\frac{a^{-2}}{1}=\frac{1}{a^2}\)
OpenStudy (anonymous):
okay let me write that down
OpenStudy (bibby):
whoops forgot about another rule. \(\huge a^m*a^n=a^{m+n}\)
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OpenStudy (anonymous):
okay what's the next step
OpenStudy (bibby):
let's cancel out the a's. give me a second to actually work it out on paper so I know what I'm doing
OpenStudy (anonymous):
from what i'm getting the answer should be A?
OpenStudy (bibby):
same. nice
OpenStudy (anonymous):
alright. very nice :)
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