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Mathematics 22 Online
OpenStudy (anonymous):

Simplify (IMAGE IN DESCRIPTION) a. c^5 y^3/a b^3 x^6 b. a^-6 c^6 y^3/a^-4 b^3 x^-9 c. a^3 c^5 y^3/ b^3 x^6 d. a^3 c^5 y^3/b^3 e. none of the above

OpenStudy (anonymous):

OpenStudy (anonymous):

@bibby

OpenStudy (bibby):

ew. let's start with the concepts. \(\large x^{-m}=\frac{1}{x^m}\) \(\large \frac{a^m}{a^n}=a^{m-n}\)

OpenStudy (bibby):

does that say b^0 on the denominator?

OpenStudy (anonymous):

yes. sorry the pic didn't come out clear.

OpenStudy (bibby):

another concept then. \(a^0=1 : x \ne 0\) anything to the 0 is 1 (except 0)

OpenStudy (anonymous):

okay so now we have a^-2/b^1

OpenStudy (bibby):

not exactly. following our rules, we have this: \(\huge \frac{a^{-2}}{b^0}=\frac{a^{-2}}{1}=\frac{1}{a^2}\)

OpenStudy (anonymous):

okay let me write that down

OpenStudy (bibby):

whoops forgot about another rule. \(\huge a^m*a^n=a^{m+n}\)

OpenStudy (anonymous):

okay what's the next step

OpenStudy (bibby):

let's cancel out the a's. give me a second to actually work it out on paper so I know what I'm doing

OpenStudy (anonymous):

from what i'm getting the answer should be A?

OpenStudy (bibby):

same. nice

OpenStudy (anonymous):

alright. very nice :)

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