How do I go about solving this complex compound interest problem with a variable?
\[50000=20000(1+\frac{ x }{ 12})^{25}\]
The first step is to divide both sides by 20,000
Doing that and then flipping the two sides gives you \[\Large \left(1+\frac{ x }{ 12}\right)^{25} = 2.5\]
The next step is to raise both sides to the power 1/25 this will cancel out the exponent of 25 on the left side of my equation above (since 25*(1/25) = 1) So we'll have \[\Large 1+\frac{ x }{ 12} = (2.5)^{1/25}\]
do you see how to finish up?
yeah, that makes a ton of sense :O!!!! Thanks!!!
Think you can help with one more :'O?
sure go ahead
\[50000=20000(1+\frac{ 0.0315 }{ 12})^{12*x}\]
what is your first step
Divide by 20000 so I end up with...\[2.5=(1+\frac{ 0.0315 }{ 12 })^{12*x}\]
good
now the next step is to somehow isolate that exponent 12x we use logs to do this
apply the log base 10 to both sides \[\Large \log(2.5)=\log\left((1+\frac{ 0.0315 }{ 12 })^{12*x}\right)\] doing this allows us to pull down the exponent 12x \[\Large \log(2.5)=12x*\log\left(1+\frac{ 0.0315 }{ 12 }\right)\] what's next?
\[0.4=12x+0.0114\]
Right...?
not quite
1+0.0315/12 = 1.002625 the log of that is log(1.002625) = 0.00113852934813 which is roughly 0.00114 which is what you got
however, it should be 12x*0.00114 on the right side
also, on the left side, I would use at least 3 decimal digits of accuracy
what I got so far is 0.3979 = 12x*0.0011385 do you see how to finish up?
x=29.12458?
About?
yes approximately
Ah ok! That makes a lot of sense!
I really can't thank you enough, you really explained it in a very understandable way.
I'm glad things are clicking now
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