can some one help me understand this problem?
let's have it :)
sin 2x = 1/2 find all solutions in 0 less than or equal to x < 360
I got the answers 15 and 75 but isnt 195 and 255 also the answer? becuase book says its not
numbers all in degrees
ok, show me how you did it real quick
and also, remember sine must be positive here
ok give me a min
kk and so long as you did it correctly, there is just one concept you need for the other angles
I'm gonna post the link, but let me see what you did before you look at it http://www.purplemath.com/modules/quadangs.htm
\[\sin \left( 180-x \right)=\sin x,\] \[\sin \left( 180+x \right)=-\sin x\] \[\sin \left( 360-x \right)=-\sin x\]
well if you do factoring and everything you get sin 2x = 1/2
and you can solve it by using two equations
x = 15 + 180k and x= 75 + 180k
the original problem was |dw:1410749563735:dw|
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