f(x) = 4x2 + 3x + 5 . using the Mean Value Theorem on the interval [-1,1]. That is, find a number c at which the instantaneous rate of change of the function f equals the average rate of change of f over the interval [-1,1].
i used the mean value theorm f'(c)=f(1)-f(-1)/1-(-1)
and you can find f(1) and f(-1) from f(x)=4x^2+3x+5
which equate to 8x+3=3
does that mean no c value exists?
nope that means you need to solve 8c+3=3 for c
c=0/8
if c occurs in the interval [-1,1] then there does exist a c in the interval [-1,1] such that f'(c)=(f(b)-f(a))/(b-a)
c=0 is a number between -1 and 1
you are done!
oh right! thanks
You do understand that 0/8=0 (and not undefined) if we had 8/0 (we wouldn't have found a number)
yea...........i got confused about that i was thinking that it was undefined opps
Yeah a lot of people do get confused about that always tried to tell them over and over if 0 is on top, you have 0 however if you have 0 on bottom, it is undefined
but if you have study limits you also know 0/0 is indeterminate form
thanks
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