Question

You have one type of chocolate that sells for $2.40/lb and another type of chocolate that
sells for $4.00/lb. You would like to have 4.8 lbs of a chocolate mixture that sells for $3.40/lb. How much of each chocolate will you need to obtain the desired mixture?

Answer 1

let x=the amount of chocolate @ 2.4
y=the amount of chocolate @ 4

2.4x+4y=4.8(3.40) ----eqn 1

x+y=4.8 -----eqn 2
x=4.8-y -----eqn 3

substitute eqn 3 to eqn 1
2.4(4.8-y)+4y=16.32
11.52-2.4y+4y=16.32
1.6y=4.8
y=3 lbs

substitute to eqn 3
x=4.8-3
x=1.8

Answer 2

you rock!!!:)

Answer 3

for some odd reason my review answer key says the answer is: 3.675 lbs. at $2.40/pound and 1.125 lbs. at $4.00/pound. Does this mean they are wrong ? lol

Answer 4

there could have been a mistake on the answer key for as long as your given problem is concerned.. ;-)