Question

Dusty planted a rectangular garden that had a perimeter of 36 yards. The length of the garden is 6 feet longer than twice the width. What is the length of the garden in feet?

Answer 1

Welcome to Open Study. Can you do algebra?

Answer 2

try to recall the perimeter of a rectangle..

Answer 3

If so, let x represent the unknown width. Now express the length in terms of the width. It says the length is 6 feet longer than twice the width. Put that down in algebra speak.
Length = 2x + 6

Answer 4

Now as shinaicantara as hinted at express the perimeter in terms of length and width.

Answer 5

I also ask do you know what perimeter is?

Answer 6

@JoseSalinas96 What is a perimeter??

Answer 7

@joseSalinas96 please participate, after all it is your problem

Answer 8

To find the perimeter add the length of the sides, there are 4 of them.

Answer 9

let x = the width of the rectangular garden
y = the length of the rectangular garden

you're given that the perimeter is 36 yards
isn't it that perimeter is twice the length plus twice the width?
so,
2x + 2y = 36 ---eq'n 1

since you're given that the length is 6 feet longer than twice the width
then you'll have:
y= 6ft(1/3(yard/ft)) + 2x
y = 2 +2x -----eqn 2

now substitute eqn 2 to eqn 1
2x + 2(2+2x) = 36
2x + 4 +4x = 36
6x = 36 - 4
6x =32
x =5.33 yards or 16 ft (width)

substitute it to eqn 2
y = 2 + 2(5.33)
y = 12.67 yards or 38 ft (length)

Answer 10

Is your answer wanted in ft or yards?

Answer 11

@JoseSalinas96 consider radar's answer though.. mine's a bit long and may cause confusion. The problem asked it in feet @radar