Question

write an equation in slope-intercept form for a line that is perpendicular to the given line and that passes through the given point

Answer 1

the problems are (-10,3); y= -2x-8
(12,8);y=-3x-9
(-1,7);y=-1/4x+6
(4,-9);-x + 2y=10
(2,1);-2x +3y=-12
(-2,3);y=-5x +1

Answer 2

refresh my memory what is the slope-intercept formula?

Answer 3

y-mx+b

Answer 4

y=mx+b*

Answer 5

you know what all the positions are so to find slope u need another point so i am only going to explain ONE and u will do the rest ok?

Answer 6

ok

Answer 7

(-10,3); y= -2x-8
sub in the -10 for the x position wat do ya get?? when you solve it

Answer 8

you get y=20-8...y=12

Answer 9

so now u have your other point and u take (-10,12) and put it in the slope formula to find the slope.. y2 - y1 divided by x2 -x1 so do that

Answer 10

i don't get that part

Answer 11

can you like do the next problem with steps and i will do the other ones by looking at your steps

Answer 12

oh sorry i have to go i cant

Answer 13

:( ok

Answer 14

To make a perpendicular line, you just take the negative reciprocals of the slope