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OpenStudy (anonymous):
Find the derivative of f(x) = 5/x at x = -1
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OpenStudy (xapproachesinfinity):
using the limit definition of derivative?
OpenStudy (xapproachesinfinity):
or you want it the usual way?
OpenStudy (bibby):
factor out the 5 and find the derivative of 1/x as we did before
OpenStudy (anonymous):
so it's 5(1/x), right?
OpenStudy (bibby):
correct. now we have \(\large 5\frac{d}{dx}\frac{1}{x}\)
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OpenStudy (anonymous):
I honestly can't remember this next part but I'm gonna take a wild guess and go with 5(1/x^2)...?
OpenStudy (bibby):
You shouldn't be guessing.
Why is that the case? What is the derivative of \(\frac{1}{x}\)?
OpenStudy (xapproachesinfinity):
oops
no guessing hehe
OpenStudy (anonymous):
x^-1?
OpenStudy (bibby):
\(\large \frac{1}{x}=x^{-1}\)
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OpenStudy (anonymous):
okay, so we plug it into the power rule now?
OpenStudy (bibby):
correct.
OpenStudy (anonymous):
f(x)=x^-1 -> -x^(-1-1) -> -x^-2
OpenStudy (bibby):
nice. yeah.
so now bring it back to the original equation.
\(\large 5\frac{d}{dx}\frac{1}{x}=5*\frac{1}{x^2}=\frac{5}{x^2}\)
OpenStudy (anonymous):
and then plug in -1 for x
so it's 5/1 or just 5?
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OpenStudy (bibby):
looks right
OpenStudy (anonymous):
It's finally making sense! Thanks :D
OpenStudy (bibby):
yay, I'm so proud ;~;
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