Write an equation in slope-intercept form for a line that is perpendicular to the given line and that passes through the given point. 40) (4,0); y=-2x 41) (0,2); x=-7 42) (0,2); y= -2x-8 43) (12,8); y=-3x-9 44) (-1,7); y=-1/4x+6 45) (4,-9); -x+2y=10 46) (2,1); -2x+3y=-12 47) (-2,3); y=-5x+1
Evaluate D(e) = 3e - 1, where e = 2. D(2) = 3(2) - 1 D(2) = 6 - 1 D(2) = 5
i don't get it...
@RampagingUbay You still there?
yes
So an equation that would meet you specifications would have a slope opposite to the given equations and when the x value for the point which it passes through is inputted, the y value of said point is derived. Did that make sense?
sorry but no...
i don't know that much english
Ok, the let's do an example problem. the equation of f(x) = -2x looks like this:|dw:1410824704097:dw| the graph of f(x) = 1/2(x) is perpendicular to f(x) = -2x like this: |dw:1410824726487:dw| Since we know that the equation f(x)=1/2x is perpendicular, we just need to add a number until f(4)=0 for f(x)=1/2x. Does this make sense?
kind of...
If you want, I could try and google translate my comments into a language you know better
no its ok
could you do a problem from the top
That was problem 40 that I just started.
Do you know what an inverse is?
is it the opposite ?
Sort of. It's the number flipped upside down. So the inverse of 3/1 would be 1/3.
can you do number 42-45 please, with out words... ?
I'd rather you be able to do them on your own first. You need to understand this concept because all required advanced math is based on things like this.
if you do it, i will look at your work and try to do the other ones please... i been stuck on those problems for a very long time
I'll do 42. y=-2x-8 perpedicular equation = y=1/2x when x=0, y must equal 2: y=1/2(0) = 0 thus, y=1/2(0) + 2 = 2 The equation is y=1/2x+2
so 43 is y=1/3x-9 y=1/3x+40
No, 43 would be y=1/3x to y=1/3x+4. where x=12, y=8 so: y=1/3(12)+4 y=4+4 y=8
where did you put the 8 ?
1/3(12) is already 4, so all you need to do to get 8 is add another 4
Binary, so #44 would be y=-4x+6 ?
Not quite, it is 4x, not -44x for the slope, meaning you need to start from the slope again
*-4x
whats with #45. it looks really wierd
you just need to simplify it to a y=mx+b form. It's just variable solving for y.
thanks for everything gtg cya
no problem
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