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5(3x-4)+4x=4(5x-2)-12 Use additive property of equality to solve for x. Please show step by step so I know If I'm doing correctly
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1) step one is distribute on both sides 2) combine like terms on both sides 3) subtract \(19x\) from both sides 4) last step...
Huh! I'm sorry but this is all new to me I would have to actually see how you did it. I got it to 20 x so I must be doing something wrong!
\[5(3x-4)+4x=4(5x-2)-12\]1) distribute gives \[15x-20+4x=20x-8-12\]
2) combining like terms gives \[19x-20=20x-20\]
2) subtract \(19x\) \[-20=x-20\] add \(20\) \[0=x\]
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Thank you. Stupid mistake. I forgot to multiply 5 with 3 x and just put down 3x! It totally changed the problem. Thank you so much!
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