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x^2=1/5, solve
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\[x=\pm\sqrt{\frac{1}{5}}\] is a start
would that be true also for lets say 2/5?
yes
and since \(\sqrt 1=1\) you might want to write \[x=\pm\frac{1}{\sqrt5}\]
or even \[x=\frac{\sqrt5}{5}\]
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okay somehow its wrong.... this is the problem they gave me 25x^4-15x^2+2=0
im to solve for it..
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