Help Please Linear Fx/Perpendicular (Medal/Fan)
Find an equation for the linear function g(x) which is perpendicular to the line 7x-6y=12 and intersects the line 7x-6y=12 at x=36.
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OpenStudy (anonymous):
So, y=(7/6)x-2
OpenStudy (anonymous):
The perpendicular would be y=(-6/7) ....I need help finding the y-intercept
OpenStudy (anonymous):
at \(x=36\) what is \(y\)?
OpenStudy (anonymous):
40?
OpenStudy (anonymous):
ok so find the equation of the line through the point \((16,40)\) with slope \(-\frac{6}{7}\)
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OpenStudy (anonymous):
ok, ill work on in real quick
OpenStudy (anonymous):
jeez why did i say \((16,40)\) doh it should be \((36,40)\)
OpenStudy (anonymous):
i dont think this is right but i got y=-6/7x+(376/7)
OpenStudy (anonymous):
OK LOL
OpenStudy (anonymous):
1 sec
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OpenStudy (anonymous):
don't do what you did!
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
\[y-40=-\frac{6}{7}(x-36)\] don't multiply out , pout in "standard form"
OpenStudy (anonymous):
\[7y-280=-6(x-36)\] etc
OpenStudy (anonymous):
never thought of it like that, ill try it, thanks. 1 sec
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OpenStudy (anonymous):
got y=-6/7x+496/7
OpenStudy (anonymous):
thats right, im sure. thank you so much!
OpenStudy (anonymous):
if you insist
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
i thought you wanted standard form
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