Question

x^2+y^2-10x=0

Answer 1

is there a question?

Answer 2

what is the center, what is the radius of the circle right?

Answer 3

Yes, sorry I'm new. I can't seem to put this in standard form to get
a center and radius.

Answer 4

\[x^2+y^2-10x=0\]
\[x^2-10x+y^2=0\] now we complete the square for the \(x\) part

Answer 5

what is half of 10?

Answer 6

5, then what do you do for y?

Answer 7

nothing

Answer 8

\(y^2\) is already a perfect square
maybe that is what is throwing you off

Answer 9

\[x^2-10x+y^2=0\\
(x-5)^2+y^2=25\]

Answer 10

clear where the \(25\) came from?

Answer 11

Yes thank you. now how do you write the center if y^2 is perfect? I understand the radius now

Answer 12

\[(x-h)^2+(y-k)^2=r^2\] and you have
\[(x-5)^2+y^2=5^5\]

Answer 13

would it help if you wrote it as
\[(x-5)^2+(y-0)^2=5^2\]?

Answer 14

So you just put a zero? I get it now! thank you so much

Answer 15

don't let your teacher see it, he or she will think you are a moron, because one write \(y-0\) but now it is clear that the center is \((5,0)\) and the radius is \(5\) right?

Answer 16

yw

Answer 17

@satellite73 is correct-a-mundo

Answer 18

yeah it was def a brain fart....