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Mathematics 17 Online
OpenStudy (anonymous):

If two dice are rolled, what is the probability that the uppermost faces do not sum to five or are not a product of 4?

OpenStudy (aum):

List all possibilities where the numbers on the dice add up to 5:

OpenStudy (anonymous):

There are 3

OpenStudy (aum):

Can you list them?

OpenStudy (anonymous):

1,4 2,3 3,2 4,1

OpenStudy (aum):

Isn't that 4 possibilities?

OpenStudy (anonymous):

oh yes sorry

OpenStudy (aum):

List all possibilities where the sum is a product of 4. That is, the sum is 4, 8 or 12.

OpenStudy (anonymous):

1,4 2,2 4,1

OpenStudy (aum):

Sum is 4: (1,3); (2,2); (3,1) Sum is 8: (2,6); (3,5); (4,4); (5,3); (6,2) Sum is 12: (6,6) Earlier, Sum is 5: (1,4); (2,3); (3, 2); (4,1) Go through the entire list and see if there are any duplicates. The count the total number of possibilities without duplicates.

OpenStudy (anonymous):

Why is product of 4 equal to sum of 4 8 and 12?

OpenStudy (anonymous):

okay theres no duplicates

OpenStudy (aum):

The question is not worded properly and can be interpreted in more than one way. "the uppermost faces do not sum to five or are not a product of 4?" The way I interpreted it is: products of 4 are: 4x1=4; 4x2=8; 4x3=12 the sum should not be a product of 4. That is, the sum should not be 4, 8 or 12.

OpenStudy (aum):

How?

OpenStudy (anonymous):

Apparently what the product one means is that die1 + die2 = 4

OpenStudy (anonymous):

I meant die 1 x die 2 = 4

OpenStudy (aum):

Yes, that is what I mean by multiple interpretation. Should the sum not be a product of 4? or Should the product not be 4?

OpenStudy (aum):

If you are sure they mean die 1 x die 2 = 4, then the possibilities are: (1,4); (2,2); (4,1)

OpenStudy (anonymous):

yes i am sure they mean that

OpenStudy (aum):

Sum is 5: (1,4); (2,3); (3, 2); (4,1) Product is 4: (1,4); (2,2); (4,1) How many distinct possibilities are there? Be careful of counting duplicates.

OpenStudy (aum):

Count ALL possibilities. Both sum is 5 and product is 4. (without duplicates)

OpenStudy (aum):

without counting the same possibility twice.

OpenStudy (anonymous):

There are 2 that satisfy both and those are (1,4) and (4,1)

OpenStudy (aum):

So don't count them a second time. How many total possibilities?

OpenStudy (anonymous):

5

OpenStudy (aum):

Yes. And if we roll a pair of dice how may total possible outcomes?

OpenStudy (anonymous):

36

OpenStudy (aum):

Yes. And the question asks: "DO NOT sum to five or are not a product of 4?" We found 5 possibilities that we don't want. So we are left with 36 - 5 = 31 desired outcomes. So the probability is: 31/36.

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