Question

3 = 0.03t^3 + 0.05t^2

Solve for t

Answer 1

Would I start by taking out t then moving 3 to the other side

\[t(0.03t^2 + 0.05t) -3 =0\]

Answer 2

@aum

Answer 3

3 = 0.03t^3 + 0.05t^2
0.03t^3 + 0.05t^2 - 3 = 0
Multiply by 100 to get rid of the decimals:
3t^3 + 5t^2 - 300 = 0

The LHS is not factorable.
But the equation can be solved for t by graphing, by numerical analysis, etc.
Which method do they want you to use?

Answer 4

They do not specify any method but I guess graphing. I did by graphing and got that t= ~4.147

Answer 5

Yes, t= ~4.147 is correct. If graphing is allowed then that would be the way to go.