Question

Evaluate: a^2 -3 (b^2-a^3)-b^0 if a= -3 and b= -5
a. -148
b. 14
c. -16
d. -142
e. none of the above

Answer 1

i got none of these as my answer

Answer 2

@jim_thompson5910

Answer 3

Plug in -3 anytime you see a and -5 anytime you see b

Answer 4

(-3)^2-3(-5^2--3^3)-(-5)^0

Answer 5

(9)-3(2)-1 then distribute
9-6-1
=2
so e

Answer 6

that's what i did. i got the same answer. so E was right then?

Answer 7

nope it's not E

Answer 8

I believe so

Answer 9

i thinks it e

Answer 10

Oh, i got the same answer as @xlilly did. what would the right way to do this be?

Answer 11

a^2 -3 (b^2-a^3)-b^0

(-3)^2 -3 (b^2-(-3)^3)-b^0 .. plug in a = -3

(-3)^2 -3 ((-5)^2-(-3)^3)-(-5)^0 .. plug in b = -5

9 -3 (25-(-27))-1

9 -3 (25+27)-1

9 -3 (52)-1

9 -156-1

-147-1

-148


So, a^2 -3 (b^2-a^3)-b^0 = -148 when a= -3 and b= -5