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Approximate rad 55 to 3 decimal places do not use calculator use only binomial expansion Theorem i got up to (49+6)^(1/2)
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(49+6)^(1/2) = n C o W^(1/2) plug it in to (W+U)^n which is nCoW^n + nC(1) W^(n-1)U ...... +nCn U^n will this work?
this is what you want http://en.wikipedia.org/wiki/Binomial_theorem#Generalisations
\[(49+6)^{1/2} = \sqrt{49} + \frac{1}{2}\frac{6}{\sqrt{49}}-\frac{1}{8} \frac{6^2}{(\sqrt{49})^3} ...\]
thank you
yw
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