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x · 1 + = _____. 1 x 1 + x 2x
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Hold on
\(x*1=x\) Kinda like how \(10*1=10\)
All numbers, times by 1, will equal that same number
All I see is �����������
lol
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xX1+x/1=
So, equatiom: \[x*1+\frac{x}{1}\]?
yes
\(x*1=x\) Therefore, we can simplfy: \[x*1+\frac{x}{1}\]\[x+\frac{x}{1}\] All numbers, that are not a fraction, can have a one as a denominator \[\frac{x}{1}+\frac{x}{1}\] Add the two numbers together \[\frac{2x}{1}\] Any number, divided by 1, equals the same number. Therefore, the answer is: \[2x\]
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