Question

1/4x - 8 + 2/4x = 19

Answer 1

x=36

Answer 2

is tht right

Answer 3

Equation:\[\frac{1}{4x}-8+\frac{2}{4x}=19\]
Convert all to have \(4x\) as the denominator\[\frac{1}{4x}+\frac{-8}{1}*\frac{4x}{4x}+\frac{2}{4x}=\frac{19}{1}*\frac{4x}{4x}\]
\[\frac{1}{4x}+\frac{-32x}{4x}+\frac{2}{4x}=\frac{76x}{4x}\]
Cancel the denominators:
\[1-32x+2=76x\]
Move the \(-32x\) to the RHS
\[1+2=108x\]
Simplify, then solve
\[3=108x\]
\[x=\frac{3}{108}\]

Answer 4

Nope, I must have got something wrong then. NVM

Answer 5

ok

Answer 6

Is the equation:
\[\frac{1}{4x}-8+\frac{2}{4x}=19\]?

Answer 7

If so, \[x=\frac{1}{36}\]
GTG, hopefully someone else can help you. Sorry :(

Answer 8

ok