Solve the system by substitution. ?
I think it wants you to do this: \(3.25x - y = -0.75\) Subtract 3.25x to both sides: \(-y = -3.25x - 0.75\) Multiply -1 to both sides: \(y = 3.25x + 0.75\) Now plug in \(3.25x + 0.75\) for y in the equation \(-4.5x - 2y = -12.5\) and solve for \(x\).
so -4.5x-2(3.25x+0.75)=12.5 ?
\(−4.5x−2y=−12.5\) \(−4.5x−2(3.25x + 0.75)=−12.5\) \(-4.5x -6.5x - 1.5 = -12.5\) \(-11x - 1.5 = -12.5\) \(-11x = -11\) \(x = 1\)
Yes, that's right @milk_cart0n
Are you seeing these? '�'
yeah what are those?
but thank you!
Idk, some glitch, just click on a different post and click back, it should be normal.
Oh alright
We're not finished yet! We have to plug in x = 1 into any of our equations to find the y-value.
\(3.25x-y=-0.75\) \(3.25(1)-y=-0.75\) \(3.25-y=-0.75\) \(-y = -4\) \(y = 4\)
So the solutions to those equations is (1, 4).
Alright that makes more sense the way you did it, i always get the substitution ones wrong
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