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OpenStudy (anonymous):
Solve for the variable c in this equation:
a(c + b) = d
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OpenStudy (kva1992):
wouldnt it be
ac + ab = d
ac= d - ab
c= d-ab/a?
OpenStudy (anonymous):
a(c-b)=d
distribute
ac-ab=d
add ab
ac=d+ab
divide by a
c=(d+ab)/a
distribute (multiply) by 1/a
c=(d/a)+b
OpenStudy (anonymous):
Ypur welcome
OpenStudy (kva1992):
you wouldnt be able to do the last step you have done
OpenStudy (anonymous):
That's not one of the answer choices if you would give me a minute I would put them down.
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OpenStudy (kva1992):
alright
OpenStudy (anonymous):
\[a(c+b)=d\]
\[ac+ab=d\]
\[ac=d-ab\]
\[c=\frac{ d-ab }{ a }\]
OpenStudy (anonymous):
\[A.) C=\frac{ d-ab }{ a }\]
\[B.) C=\frac{ d+ab }{ a }\]
\[C.) C=\frac{ ab-d }{ a }\]
\[D.) C= \frac{ d-ab }{ b }\]
OpenStudy (anonymous):
I think it's B.
OpenStudy (anonymous):
@rydertheepic
its a(c+b)=d
not a(c-b)=d
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OpenStudy (anonymous):
A is the best answet
OpenStudy (kva1992):
i already did that lol
OpenStudy (kva1992):
i told you it was lol
OpenStudy (kva1992):
scroll up to the post and i showed exactly how you do it
OpenStudy (anonymous):
are u saying this to me @kva1992
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OpenStudy (kva1992):
nope lol
OpenStudy (kva1992):
i was just saying i already stated that lol crazy went over my post lol
OpenStudy (kva1992):
by any chance do you want to help me out on my question lol?
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