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Mathematics 7 Online
OpenStudy (anonymous):

Solve for the variable c in this equation: a(c + b) = d

OpenStudy (kva1992):

wouldnt it be ac + ab = d ac= d - ab c= d-ab/a?

OpenStudy (anonymous):

a(c-b)=d distribute ac-ab=d add ab ac=d+ab divide by a c=(d+ab)/a distribute (multiply) by 1/a c=(d/a)+b

OpenStudy (anonymous):

Ypur welcome

OpenStudy (kva1992):

you wouldnt be able to do the last step you have done

OpenStudy (anonymous):

That's not one of the answer choices if you would give me a minute I would put them down.

OpenStudy (kva1992):

alright

OpenStudy (anonymous):

\[a(c+b)=d\] \[ac+ab=d\] \[ac=d-ab\] \[c=\frac{ d-ab }{ a }\]

OpenStudy (anonymous):

\[A.) C=\frac{ d-ab }{ a }\] \[B.) C=\frac{ d+ab }{ a }\] \[C.) C=\frac{ ab-d }{ a }\] \[D.) C= \frac{ d-ab }{ b }\]

OpenStudy (anonymous):

I think it's B.

OpenStudy (anonymous):

@rydertheepic its a(c+b)=d not a(c-b)=d

OpenStudy (anonymous):

A is the best answet

OpenStudy (kva1992):

i already did that lol

OpenStudy (kva1992):

i told you it was lol

OpenStudy (kva1992):

scroll up to the post and i showed exactly how you do it

OpenStudy (anonymous):

are u saying this to me @kva1992

OpenStudy (kva1992):

nope lol

OpenStudy (kva1992):

i was just saying i already stated that lol crazy went over my post lol

OpenStudy (kva1992):

by any chance do you want to help me out on my question lol?

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