How do you find the domain and range f(x)=3+5times the square root of x

Question

anonymous · Answer

$$y=3+5\sqrt{x}$$. The thing under the square root must be non negative to be defined. The thing under the square root is x. So x must be greater than or equal to zero. Therefore $$x \in [0,\infty)$$ is the domain. (That basically means any number x greater than or equal to zero. )

anonymous · Answer

The lowest x we can have is x = 0. When x = 0 then y = 3. So the lowest value our y can have is 3. There is no highest value our y can have so it can go to infinity. Therefore the range is any number greater than 3. which can be written as $$y \in [3,\infty)$$

anonymous · Answer

The domain is $$x \in[0,\infty)$$ and the range is $$y \in[3,\infty)$$