Question

Molarity of standardized NaOH solution is 0.1012
final buret reading, mL IS 31.21
INITIAL buret reading, mL IS 15.72
VOLUME OF TITRANT, mL is 15.49
Moles of NaOH used is 1.568*10^-3 mol
Moles of HC2H302 neutralized by the NaOH is 1.568*10^-3 Mol
Molarity of dill HC2H302 is .0783
avearge molarity of diluted vinegar is 0.7865 M
the deviation di is .000350

Answer 1

find moralty of original vingar

Answer 2

you've already solved for it, what's the problem?

Answer 3

i didnt solve it yet

Answer 4

did I

Answer 5

First off what you have written is pretty confusing, write complete words dont use dill, what did you do? What is the experimental data and what data is given.

Answer 6

dill is diluted

Answer 7

this is the summary of titration data and data anaysis

Answer 8

Try to be more clear in the future when asking questions dont waste peoples time especially those that are trying to help you. Anyways:

So you have determined experimentally that the unknown had a concentration of 0.0783M of acetic acid

so,
experimental value = 0.0783M

I assume it was given to you that, the mean or average concentration of acetic acid in these unknown samples is 0.7865 M

so,
True value = 0.7865 M

Use, the formula that aaronq gave you

\[avg.\; deviation = \frac{|True\; value - Experimental\; Value|}{True\; Value}\]

Answer 9

.7865 is what I caulated, it was not given

Answer 10

wel no there were four experiments data

the first one was .0783
the secned was .0785
the third was .0789
the fourth was .0789

Answer 11

i caculated the average deviation which is .00025 right

Answer 12

Then what is the problem?

Answer 13

you want me to check it for you?

Answer 14

Look you cant expect me to want to help you if you are not even going to pose the question in a clear manner. I have better things to do.

Answer 15

i found that and I found the relative deviation @aaronq helped me with that

Answer 16

the relative deviation is 3.18 parts per thousand (ppt)

Answer 17

now ther are asking me to find the molarity of original vinegar

Answer 18

how do i do this

Answer 19

i have to find the molarity of orgianl vingar

then find the wieght percent HC2H302 in original vinegar

Answer 20

how do i do that

Answer 21

The molarity of the original vinger I would assume would be the average of all your samples molarity.

Using the average molarity of all your samples find the moles using this formula:

Molarity = Moles/Litres

Then convert moles to grams using:

moles = grams/molecular mass

Then use the formula

Weight % = Grams of acetic acid/mL of solution

Answer 22

If you have any questions feel free to ask

Answer 23

@aaronq

Answer 24

@aaronq then please unbock me so i dont have to write in peoples stuff

Answer 25

i can just meesage you @aaronq

Answer 26

and what is the avarge molarity

Answer 27

what would that be

Answer 28

@aaronq

Answer 29

@aaronq

Answer 30

the first one was .0783
the secned was .0785
the third was .0789
the fourth was .0789

Average these values these are molarity values right?

Answer 31

.3146

Answer 32

RIGHT