Question

Solve the following circuit.

Answer 1

I began by combining the 33k and 20k resistor. Im stuck after that.

Answer 2

This looks like a lab exercise, but with what is furnished you can:
Since Vs is 8 volts (given) you can calculate the current in the circuit which would be I=E/R (Ohms Law) I= 8/(47K + 33k + 20k) = 8/100k = .08 milliamp.

The voltage V4 is simply the sum of the voltage drops across the 33K and 20K resistors labeled V1 and V2 again using Ohms Law V1=.08 X 20K =1.6 Volts. In a similar manner calculate V2, V2= .08 X 33K = 2.64. V4= V1 + V2 = 1.6 + 2.64 = 4.24 Volts. The Voltage could be calculated two ways, V3=.08 X 47K= 3.76 Volts and using the fact the sum of the drops equals the source. V3= 8 -1.6 - 2.64 = 3.76 Volts.

Is there more you want to know about this circuit?.

Answer 3

@SilenTempest Did you follow this?

Answer 4

Be sure and do the lab to verify, and get some practice with the lab equipment.

Answer 5

@radar Thank you. I actually did not notice that V4 was just voltage across v2+V3. I got everything you put. Thank you!