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Mathematics 7 Online
OpenStudy (anonymous):

5x^2+1=51

OpenStudy (anonymous):

subtract \(1\) get \[5x^2=50\] divide by \(5\) get \(x^2=10\) is a start

OpenStudy (anonymous):

finish by taking the square root, don't forget the \(\pm\)

OpenStudy (anonymous):

so, 5x^2=50 5x^2/5=50/5 x^2=10 √x^2=√10 x=+√10 and -√10 @satellite73

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

much clearer thanks again!

OpenStudy (anonymous):

well to be real picky it should be \[x=\sqrt{10}\] OR \[x=-\sqrt{10}\]

OpenStudy (anonymous):

yw

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