Find the zeros of the polynomial function and state the multiplicity of each
f(x)=5(x+7)^2(x-7)^3
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OpenStudy (anonymous):
can you walk me through the steps @***[ISURU]*** ?
OpenStudy (anonymous):
@***[ISURU]***
OpenStudy (***[isuru]***):
How far did you went on this one ?... did you manage to find the zeros of this polynomial ?
OpenStudy (anonymous):
I do not know how to work this problem. I need someone to show me how to solve it. :D
OpenStudy (***[isuru]***):
lets take the polynomial
p(x) = 5(x+7)(x-7)
Its the same polynomial as your question but without the powers of 2 and 3
now to find the zeros...
lets find the "x" values when p(x) = 0
0 = 5(x+7)(x -7)
now can you find the "x" values where this function will become zero ?
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OpenStudy (anonymous):
would you do x+7=0 and x-7=0 ?
OpenStudy (***[isuru]***):
yes...and what will you get ? :)
OpenStudy (anonymous):
-7 and 7
OpenStudy (anonymous):
ok so the answer would -7 multiplicity 2 and 7 multiplicity 3 right?
OpenStudy (***[isuru]***):
You got it correct ! :)
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