Which point lies on the graph of this function?
y=-x^2+4x-2
(-1,3)
(0,2)
(1,1)
(2,-2)

Can someone help me with this I don't know where to start.

Question

Which point lies on the graph of this function?
y=-x^2+4x-2
(-1,3)
(0,2)
(1,1)
(2,-2)

Can someone help me with this I don't know where to start.

campbell_st · Answer

just substitute the x value for each point into the equation and see if you get the y value from the point

anonymous · Answer

Ohh okay thank you

anonymous · Answer

none of them worked

anonymous · Answer

wait I messed up I forgot the negative sign out in front

campbell_st · Answer

I think its the negative to start check (1, 1)

y = -(1)^2 + 4(1) - 2

so 

y = -1 + 4 - 2

y = 1

so it looks like (1, 1) is the answer