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The average (arithmetic mean) of 5 numbers is 13. If the average of 4 of these numbers is 10, what is the fifth number?
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We know that five numbers, (x+y+v+z+w)/5 = 13, and that four numbers, (x+y+v+z)/4 = 10. If we say that x+y+v+z = a, then we have two solveable equations, wouldn't you say?
is it 25..
yeah im failing this class so i couldnt tell you haha
You just have to solve for a, then sub it into the second equation to find w. \[\frac{ a }{ 4} = 10.........(1)\] \[\frac{ a+w }{ 5 }.......(2)\]
Sorry, that second equation should have an = 13 at the end of it
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\(\large\tt \color{black}{take~~the~~five~~numbers~~as~~(x-3a),(x-a)(x),(x+a)(x+3a)}\)
avg of 5 @13 =65 avg of 4 @10=40 therefore,65-40=25
5th no is 25
nice..
ty all<3
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