Question

A motorist traveling at 10 m/s encounters a
deer in the road 40 m ahead.
If the maximum acceleration the vehicle’s
brakes are capable of is −7 m/s
2
, what is the
maximum reaction time of the motorist that
will allow her or him to avoid hitting the deer?
Answer in units of s
If his or her reaction time is 3.38571 s, how
fast will (s) he be traveling when (s)he reaches
the deer?
Answer in units of m/s

Answer 1

i found the answer to the first question is 3.286 but i dont know how to do the second question.

Answer 2

hellooo??

Answer 3

if his reaction time is 3.38571 then distance travelled before he could is = 3.38571 x 10 = 33.5871

Answer 4

if his reaction time is 3.38571 then distance travelled before he could react is = 3.38571 x 10 = 33.5871

Answer 5

calculate the remaining distance

Answer 6

and use the formula \[v^{2} = u^{2} +2as\]

Answer 7

where u is initial velocity .. that is 10

v is the final velocity which we have to calculate ..

a is the acceleration = -7

and s is the remaining distance

Answer 8

thank yuuuu!!