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1/x+1/(x+2)=1/3
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What are you having trouble with?
solving quadratics and finding the descriminant
I don't know wr to start
Start by combining the 1/x and the 1/(x+2)
Can you do that?
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do i set both denominators as (x+2)?
As x(x+2). You can't set the first denominator as x+2 because nothing you multiply it by will give you that.
oh I see thanks
this might be wrong but would you get 2/x(x+2)? or 2x/x(x+2)
Just treat it like a fraction. \[\frac{ 1 }{ x }*\frac{ x+2 }{ x+2 } + \frac{ 1 }{ x+2 }*\frac{ x }{ x }\] \[\frac{ x+2 }{ x(x+2)}+\frac{ x }{ x(x+2) }\] \[\frac{ 2x+2 }{ x(x+2) }\]
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thanks
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