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Mathematics 14 Online
OpenStudy (anonymous):

1/x+1/(x+2)=1/3

OpenStudy (anonymous):

What are you having trouble with?

OpenStudy (anonymous):

solving quadratics and finding the descriminant

OpenStudy (anonymous):

I don't know wr to start

OpenStudy (anonymous):

Start by combining the 1/x and the 1/(x+2)

OpenStudy (anonymous):

Can you do that?

OpenStudy (anonymous):

do i set both denominators as (x+2)?

OpenStudy (anonymous):

As x(x+2). You can't set the first denominator as x+2 because nothing you multiply it by will give you that.

OpenStudy (anonymous):

oh I see thanks

OpenStudy (anonymous):

this might be wrong but would you get 2/x(x+2)? or 2x/x(x+2)

OpenStudy (anonymous):

Just treat it like a fraction. \[\frac{ 1 }{ x }*\frac{ x+2 }{ x+2 } + \frac{ 1 }{ x+2 }*\frac{ x }{ x }\] \[\frac{ x+2 }{ x(x+2)}+\frac{ x }{ x(x+2) }\] \[\frac{ 2x+2 }{ x(x+2) }\]

OpenStudy (anonymous):

thanks

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