Help my brain is overloading!!! Given f(x)= x^2-2x-1 find f(x^2+3) I got x^4-2x^2+2 but its x^4-4x^2+2
can you tell me why its 4 rather than 2?
probably algebra
this problem has been bothering me for the last 2 hours im so frustrated
\[f(x)= x^2-2x-1\]\[ f(x^2+3) =(x^2+3)^2-2(x^2+3)-1\]
it isnt worth that much of your time
yea thats exactly what i did and i got my answer
course i didn't do it, maybe your answer is correct shall we check?
but i don't understand why its a 4x^2 rather than 2x^2
\[(x^2+3)^2=x^4+6x^2+9\]
when you subtract the \(2x^2\) from the second term you will be left with \(4x^2\) did you forget to square correctly?
why is it 6x^2
tsk tks, you deserve to lose two hours if you forgot how do square something please don't tell me you think \((a+b)^2=a^2+b^2\) when it is really \[(a+b)^2=a^2+2ab+b^2\]
wait but why do you do 2ab tho? i don't understand .... its not like we're factoring anything here
you don't "do" anything, you multiply \[(x^2+3)^2=(x^2+3)(x^2+3)=x^4+3x^2+3x^2+9=x^4+6x^2+9\]
wow......
okay im super stupid....
wow...... *facepalm* okay thanks ...
yw
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