!!!!!!!!!!!!!!!(Quick help please)
Write equation in slope intercept form.
Passing through (-5,9) and perpendicular to the line whose equation is y+1=5/6(x-7).
(Since this is in point-slope form how do I make it into slope-intercept, do I just add the point (-5,9) to the y+1 (y+1-5) and (x-7-9)? )

Question

!!!!!!!!!!!!!!!(Quick help please)
Write equation in slope intercept form.
Passing through (-5,9) and perpendicular to the line whose equation is y+1=5/6(x-7).
(Since this is in point-slope form how do I make it into slope-intercept, do I just add the point (-5,9) to the y+1 (y+1-5) and (x-7-9)? )

triciaal · Answer

given y+1=5/6(x-7).
slope = 5/6 = m 
slope of perpendicular = -1/m = -1/(5/6) = -6/5
passing through (-5, 9)
y-9= -6/5(x -     -5) = -6/5(x + 5) 
add 9 to each side to change to slope intercept form, y = m x + b 
y = -6/5x + (9 - 6)
y = -6/5 x + 3

triciaal · Answer

any questions?