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x^2+3x-9=0 completing the square. please will appreciate if working is shown.
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a = 1 b = 3 and c = -9 what is -b/2a =
can you respond?
sorry just got back
let me explain with general equation and see of that makes sense to you. starting with \[x^2 +bx+c=0\] you want the equation to end up looking like \[(x+h)^2 + k = 0\] expanding the square: \[x^2 +2hx +h^2 +k = 0\] this means \[b = 2h \rightarrow h = \frac{b}{2}\] and \[c = h^2 +k \rightarrow k = c - h^2\]
For your example; b= 3 c = -9 so \[h = \frac{b}{2} = \frac{3}{2}\] \[k = c - h^2 = -9 - (\frac{3}{2})^2\]
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