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Calculus1
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integral(1/(xsqrt(1+ln(x)^2)dx
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\[\int\limits \frac{ 1 }{ x \sqrt{1+\ln^2} }dx\]
u=ln(x) du=1/xdx dx=xdu
\[\int\limits \frac{ 1 }{ \sqrt{1+u^2}}du\]
we can't use the identity so do I have to do a trig sub for this?
u=sin(theta) dx=cos(theta)
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but when I try this: \[\int\limits\frac{ 1 }{ \sqrt{1+\sin^2}(\theta) }\cos(\theta)d(\theta)\]
and simplify i get down to \[\int\limits \frac{ 1 }{ \cos(\theta) }\cos(\theta)d(\theta)\] and \[\int\limits1d(\theta)\]
i get stuck
what is arcsinh?
inverse hyperbolic function and arcsinhx = log (x+sqrt(x^2+1)) Source: http://www.mathskey.com/question2answer/
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