We connect a battery of 2.5 volts with a 0.5 ohms resistor, so a current of 2 amperes intensity passes. If we replaced the resistor with another one of 1.75 ohms, find the current intensity.

Question

mrnood · Answer

the word 'intensity' is redundant in the question.

It is the current that flows.

This is about internal rsistance.

The current has to flow throught the external resistance AND through the battery.

Ohms law says I = V/R

Internal resistance is in series with the external resistance

so for the initial circuit 2 Amps = 2.5 V/R(total)

So you can work out R(total)

For series resistors (R total) = r1 + r2 and you know external resistance = 0.5 ohms

So oyu can work out the internal resistance.

Then use the same rule, with external resistance = 1.75 Ohms to work out th ecurrent through tne revised circuit