Question

Can someone please help me with my Algebra 2 homework?
How do I solve the system using the substitution method?
3x + 7y = 13 Equation 1
x + 3y = -7 Equation 2

Answer 1

3x + 7y = 13 ---- eqn1
x + 3y = -7 ------ eqn 2

from equation 2, you'll get
x = -3y -7 ----eqn 3
substitute eqn 3 to eqn 1
3x + 7y = 13
3(-3y-7) + 7y = 13
-9y - 21 + 7y = 13
-2y = 13 +21
-2y = 34
y = -17
substitute the value for y to eqn 3 to get x
x = -3y -7
= -3(-17) - 7
= 44